Home
Class 11
CHEMISTRY
Two inflated ballons I and II (thin skin...

Two inflated ballons I and II (thin skin) having volume 600 mL and 1500 mL at 300 K are taken as shown in diagram. If maximum volume of inner and outer balloons are 800 mL and 1800 mL respectively then find the balloon which will burst first on gradual heating.

A

inner balloon

B

outer balloon

C

both simultaneously

D

unpredictable

Text Solution

Verified by Experts

The correct Answer is:
b
(b) Case `I-` Suppose inner balloon burst first first
`(600)/(300)=(800)/(T_(2))impliesT_(2)=400K`
Case `II-`Suppose inner balloon burst first
`(1500)/(300)=(1800)/(T_(2))," "T_(2)=360K`
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|1 Videos

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.121 To Q.150)|1 Videos

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Assertin-Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

Two thin metallic spherical shells of radii 20 cm and 30 cm, respectively are placed with their centres coinciding. A material of thermal conductivity alpha is filled in the space between the shells. The inner shell is maintained at 300 K and the outer shell at 310 K. If the rate at which heat flows radially through the material is 40 W, find the value of alpha (in units of Js^(-1)m^(-1)K^(-1) ).

A flask of 1L having NH_(3)(g) at 2.0atm and 200K is connected with another flask of vol 800ml having HCl(g) at 8atm & 200K through tube of negligible volume. The two gases reacts to form NH_(4)Cl(s) with evolution of 43 KJ/mol heat. If heat capacity of at constant volume is 20J/K/mol and neglecting heat capacity of flask and solid, volume of solid formed and its pressure (R = 0.08). The final pressure in the flask is

H_2O_2 + 2KI overset("40% yield")to I_2 + 2KOH H_2O_2 + 2KMnO_4 + 3H_2SO_4 overset("50% yield ")to K_2SO_4 + 2MnSO_4 + 3O_2 + 4H_2O 150 ml of H_2O_2 sample was divided into two parts. First part was treated with KI and Formed KOH required 200 ml. of M//2 H_2SO_4 for neutralisation.Other part was trated with KMnO_4 yielding 6.74 litre of O_2 at STP.Using % yield indicated find volume stregth of H_2O_2 sample used.