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A rigid vessel of volume 0.50m^(3) cont...

A rigid vessel of volume ` 0.50m^(3)` containing `H_(2) ` at `20.5^(@)C` and a pressure of `611 xx 10^(3)` Pa is connected to a second rigid vessel of volume 0.75`m^(3)` containing Ar at `31.2^(@)C` at a pressure of `433xx10^(3)` Pa. A value separating the two vessels is opened and both are cooled to a temperature of `14.5^(@)C`. What is the final pressure in the vessels?

A

`2xx10^(5)`

B

`3.22xx10^(5)" Pa"`

C

4840 pa

D

`4.84xx10^(5)" Pa"`

Text Solution

Verified by Experts

The correct Answer is:
d
(d) `n_(T)=n_(2)+n_(2) `
`(Pxx1.25)/(Rxx287.5)=(611xx10^(3)xx0.5)/(293.5 R)+(433xx10^(3)xx0.75)/(204.5R)`
`P=4.84xx10^(5)Pa`
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