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O(2) and SO(2) gases are filled in ratio...

`O_(2)` and `SO_(2)` gases are filled in ratio of 1 : 3 by mass in a closed container of 3 L at temperature of `27^(@)C`. The partial pressure of `O_(2)` is 0.60 atm, the concentration of `SO_(2)` would be

A

0.36

B

0.036

C

3.6

D

36

Text Solution

Verified by Experts

The correct Answer is:
b
(b) We have `P_(O_(2))=X_(O_(2))xxP_("total")`
`:." " 0.60=(n_(O_(2)))/(n_(O_(2))+n_(SO_(2)))xxP_("total")`
Let no. of moles of `O_(2)` are `x,`
`0.60=(x//32)/(x//32+3x//64)xxP_("total")`
`:. 0.60=0.4xxP_("total")`
`:. " "P_("total")=(0.60)/(0.4)=1.5"atm"`
`:'P_(O_(2))+P_(SO_(2))=1.5"atm"`
`implies P_(SO_(2)) =1.5-P_(O_(2))=1.5-0.60=0.9"atm"`
`:. "Concentration of "SO_(2)=(0.9)/(0.0821xx300)`
`=0.036`
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