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A gaseous mixture of three gases A, B an...

A gaseous mixture of three gases A, B and C has a pressure of 10atm. The total number of moles of all the gases is 10. The partial pressure of A and B are 3 and I am respectively. If C has a molecular weight of 2, what is the weight of C in grams present in the mixture?

A

8 g

B

12 g

C

3 g

D

6 g

Text Solution

Verified by Experts

The correct Answer is:
b
(b) Given P = 10 atm,
total numbers of moles, `n_(A)+n_(B)+n_(C)=10`
`P_(A)=3"atm," P_(B)=1"atm," n_(A)=3,n_(B)=1`
`:' P_(A)=x_(A)xxP_(("total"))=(n_(A))/(n_(A)+n_(B)+n_(C))xx10`
`=(n_(A))/(10)xx10n_(A)=3`
Similarly, `P_(B)=x_(B)xxP_("total")`
So, `n_(B)=1`
`:. " " n_(C)=10-(n_(A)+n_(B))=10-4=6`
Mass of `C=6xx2=12g`
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