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One mole of a monoatomic gas is mixed wi...

One mole of a monoatomic gas is mixed with one mole of a diatomic gas. What will be the `gamma` for the mixture?

A

1.4

B

1.5

C

1.53

D

3.07

Text Solution

Verified by Experts

The correct Answer is:
b
(b) `{:(C_(v)=(3)/(2)RT),(C_(p)=(5)/(2)RT):}` for monoatomic gas,
`{:(C_(v)=(5)/(2)2RT),(C_(p)=(7)/(2)RT):}` for diatomic gas
Thus, for mixture for 1 mole each,
`C_(v)=((3)/(2)RT+(5)/(2)RT)/(2)`
`and" "C_(p)=((5)/(2)RT+(7)/(2)RT)/(2)`
Thus, `(C_(p))/(C_(v))=(3RT)/(2RT)=1.5`
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