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The pressure of real gas is less than th...

The pressure of real gas is less than the pressure of an ideal gas because of

A

increase in number of collisions

B

finite size of molecule

C

increase in KE of molecules

D

intermolecular forces of attraction

Text Solution

Verified by Experts

The correct Answer is:
d
(d) `P_("Ideal")=P_("Real")+(n^(2)a)/(V^(2))`
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