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The compressibility factor for a real ga...

The compressibility factor for a real gas at high pressure is .

A

1

B

`1+(Pb)/(RT)`

C

`1-(Pb)/(RT)`

D

`1+(RT)/(Pb)`

Text Solution

Verified by Experts

The correct Answer is:
b
(b) van der Waals' equation for one mole of a real gas is
`(P+(a)/(V^(2)))(V-b)=RT`
`or" "PV=RT+Pb+(ab)/(V^(2))-(a)/(V)`
At high pressures, the van der Waals' gas equation reduces to PV =RT + Pb
`or " "(PV)/(RT)=1+(Pb)/(RT)`
`:.` Compressibility factor Z `=(PV)/(RT)=1+(Pb)/(RT)`
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