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The compressibility factor for nitrogen ...

The compressibility factor for nitrogen at `330K` and `800 atm` is `1.90` and at `570K` and `200 atm` is `1.10`. A certain mass of `N_(2)` occupies a volume of `1dm^(3)` at `330K` and `800 atm` calculate volume occupied by same quantity of `N_(2)` gas at `570 K` and `200 atm`

A

1 L

B

2 L

C

3 L

D

4 L

Text Solution

Verified by Experts

The correct Answer is:
d
(d) `Z=(PV)/(nRT),1.90=(1xx800)/(nxxRxx330),`
`n=(1xx800)/(1.90xxRxx330)`
`Z=1.10=(Vxx200)/(nxxRxx570),`
`1.10=(Vxx200xx1.90xxRxx330)/(800xxRxx570)`
`V=4 L`
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