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Calculate the volume occupied by 16 grm ...

Calculate the volume occupied by 16 grm `O_(2)` at 300 K and 8.31 MPa if `(P_(c)V_( c))/(RT_( c))= 3/8` and `(P_(t)V_(t))/T_(t)=2.21` (Given : R = 8.314 Mpa/K-mol)

A

125.31 mL

B

124.31 mL

C

248.62 mL

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
b
(b) `(P_(r)V_(r))/(T_(r))=2.21`
` (P)/(P_(C))xx(V)/(V_(C))xx(T_(C))/(T)=2.21`
`(PV)/(T)xx(T_(C))/(P_(C)V_(C))=2.21`
`=0.1243L=124.31mL`
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