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The van der Waals' constant 'b' of a gas...

The van der Waals' constant 'b' of a gas is `4pixx 10^(-4)L//mol.` How near can the centeres of the two molecules approach each other? [Use :`N_(A)=6xx10^(23)`]

A

`10^(-7)` m

B

`10^(-10)` m

C

`5xx10^(-11)` m

D

`5xx10^(-9)` m

Text Solution

Verified by Experts

The correct Answer is:
b
(b) `b=4xx(4)/(3)xxpir^(3)xxN_(A),`
`4xxpixx10^(-4)xx1000`
`4xx(4)/(3)xxpixxr^(3)xx6xx10^(23)`
`r=5xx10^(-9)cm`
Distance of closest approach `=2r`
`=10^(-8)cm " or "10^(-10)m`
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