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The time for a certain volume of a gas A...

The time for a certain volume of a gas `A` to diffuse through a small hole is 2 minute If takes 5.65 minute for oxygen to diffuse under similar conditions Find the molecualr weight of `A` .

Text Solution

Verified by Experts

The correct Answer is:
4
`(r_(x))/(r_(O_(2)))=sqrt((M_(O_(2)))/(M_(x)))`
`(V)/(2)xx(5.65)/(V)=sqrt((32)/(M))`
`8=(32)/(M)`
`M=4`
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