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Initially bulb "a" contained oxygen gas ...

Initially bulb "a" contained oxygen gas at `27^(@)C` and 950 mm of Hg and bulb "B" contained neon gas at `27^(@)C` and 900 mm of Hg. These bulbs are connected by a narrow tube of negligible volume equipped with a stopcock and gases were allowed to mix-up freely. The pressure obtained in the combined system was found to be 910 mm of Hg.

If volume of bulb B was measured to be 10 L, then find the volume of oxygen gas present initially in bulb "A" .

Text Solution

Verified by Experts

The correct Answer is:
4
`n_(T)=n_(1)+n_(2)`
`(910xx(10+V))/(RT)=(950xxV)/(RT)+(900xx10)/(RT)`
`V=4L`
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