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The ratio of curved surface area to tota...

The ratio of curved surface area to total surface area of a cylinder is 7:9. Find diameter of cylinder, if volume of cylinder is `88 cm^(3).`

A

4 cm

B

2 cm

C

9 cm

D

7 cm

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The correct Answer is:
To solve the problem step by step, we will follow the given information and formulas related to the cylinder. ### Step 1: Understand the given information We know that the ratio of the curved surface area (CSA) to the total surface area (TSA) of a cylinder is 7:9, and the volume of the cylinder is 88 cm³. ### Step 2: Write the formulas The formulas for the curved surface area and total surface area of a cylinder are: - Curved Surface Area (CSA) = \(2 \pi r h\) - Total Surface Area (TSA) = \(2 \pi r (r + h)\) ### Step 3: Set up the ratio Given the ratio of CSA to TSA: \[ \frac{CSA}{TSA} = \frac{7}{9} \] Substituting the formulas: \[ \frac{2 \pi r h}{2 \pi r (r + h)} = \frac{7}{9} \] This simplifies to: \[ \frac{h}{r + h} = \frac{7}{9} \] ### Step 4: Cross-multiply to solve for h Cross-multiplying gives: \[ 9h = 7(r + h) \] Expanding the right side: \[ 9h = 7r + 7h \] Rearranging gives: \[ 9h - 7h = 7r \implies 2h = 7r \] Thus, we can express \(h\) in terms of \(r\): \[ h = \frac{7}{2}r \] ### Step 5: Write the volume formula The volume \(V\) of the cylinder is given by: \[ V = \pi r^2 h \] Substituting the volume and the expression for \(h\): \[ 88 = \pi r^2 \left(\frac{7}{2}r\right) \] This simplifies to: \[ 88 = \frac{7}{2} \pi r^3 \] ### Step 6: Solve for \(r^3\) Rearranging gives: \[ r^3 = \frac{88 \times 2}{7 \pi} \] Calculating the right side: \[ r^3 = \frac{176}{7 \pi} \] ### Step 7: Substitute the value of \(\pi\) Using \(\pi \approx 22/7\): \[ r^3 = \frac{176}{7 \times \frac{22}{7}} = \frac{176}{22} = 8 \] ### Step 8: Find \(r\) Taking the cube root: \[ r = \sqrt[3]{8} = 2 \text{ cm} \] ### Step 9: Find the diameter The diameter \(d\) of the cylinder is given by: \[ d = 2r = 2 \times 2 = 4 \text{ cm} \] ### Final Answer The diameter of the cylinder is **4 cm**. ---
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