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Perimeter of a right angled triangle is ...

Perimeter of a right angled triangle is 60m and length of hypotenuse of right angled triangle is 25m. If base of the right angled triangle is the smallest side, then find length of smallest side.

A

A)15m

B

B)18m

C

C)21m

D

D)25m

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the Problem We have a right-angled triangle with: - Perimeter = 60 m - Hypotenuse = 25 m We need to find the length of the smallest side, which is the base of the triangle. ### Step 2: Set Up the Equation for the Perimeter The perimeter of a triangle is the sum of the lengths of its sides. Let: - \( a \) = length of the smallest side (base) - \( b \) = length of the other side (height) - \( c \) = length of the hypotenuse = 25 m The equation for the perimeter is: \[ a + b + c = 60 \] Substituting the value of \( c \): \[ a + b + 25 = 60 \] ### Step 3: Simplify the Equation Now, we can simplify the equation to find the relationship between \( a \) and \( b \): \[ a + b = 60 - 25 \] \[ a + b = 35 \] ### Step 4: Use the Pythagorean Theorem Since it is a right-angled triangle, we can use the Pythagorean theorem: \[ a^2 + b^2 = c^2 \] Substituting the value of \( c \): \[ a^2 + b^2 = 25^2 \] \[ a^2 + b^2 = 625 \] ### Step 5: Solve the System of Equations Now we have two equations: 1. \( a + b = 35 \) 2. \( a^2 + b^2 = 625 \) From the first equation, we can express \( b \) in terms of \( a \): \[ b = 35 - a \] Substituting this into the second equation: \[ a^2 + (35 - a)^2 = 625 \] ### Step 6: Expand and Simplify Expanding the equation: \[ a^2 + (35^2 - 70a + a^2) = 625 \] \[ 2a^2 - 70a + 1225 = 625 \] \[ 2a^2 - 70a + 600 = 0 \] ### Step 7: Divide the Equation To simplify, divide the entire equation by 2: \[ a^2 - 35a + 300 = 0 \] ### Step 8: Use the Quadratic Formula Now we can use the quadratic formula to find \( a \): \[ a = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -35, c = 300 \): \[ a = \frac{35 \pm \sqrt{(-35)^2 - 4 \cdot 1 \cdot 300}}{2 \cdot 1} \] \[ a = \frac{35 \pm \sqrt{1225 - 1200}}{2} \] \[ a = \frac{35 \pm \sqrt{25}}{2} \] \[ a = \frac{35 \pm 5}{2} \] ### Step 9: Calculate the Values Calculating the two possible values for \( a \): 1. \( a = \frac{40}{2} = 20 \) 2. \( a = \frac{30}{2} = 15 \) ### Step 10: Determine the Smallest Side Since we are given that the base is the smallest side, we take: - \( a = 15 \) m (smallest side) - \( b = 20 \) m (other side) ### Final Answer The length of the smallest side (base) is **15 m**. ---
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