The energy of a photon is given as `3.03 xx 10^(-19) J// "atom"`. The wavelength of the photon is :-

Options

A. 6.56 nm
B. 65.6 nm
C. 0.656 nm
D. 656 nm

Answer

D

Explanation

`E="hc"/lambda`
`lambda=(6.6 xx 10^(-34) xx 3 xx 10^8)/(3.03 xx 10^-19)`
`lambda=6.56 xx 10^-7 m`
`lambda= 656 nm`