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Find the moment of inertia of a disc of ...

Find the moment of inertia of a disc of mass 3 kg and radius 50 cm about the following axes.
axis passing through the center and perpendicular to the plane of the disc,

Text Solution

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The mass, M = 3 kg, radius R = 50 cm = `50 × 10^(−2)` m = 0.5 m
e moment of inertia (I) about an axis passing through the center and perpendicular to the plane of the disc is,

`I=(1)/(2)MR^(2)`
`I=(1)/(2)xx3xx(0.5)^(2)=0.5xx3xx0.5xx0.5`
`I=0.375kgm^(2)`
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