Find the moment of inertia of a disc of mass 3 kg and radius 50 cm about the following axes.
axis passing through the center and lying on the plane of the disc.

Explanation

The moment of inertia (I) about an axis passing through the center and lying on the plane of the disc is,

`I_(Z)=I_(X)+I_(Y)`
where, `I_(X)=I_(Y)=I and I_(Z)=(1)/(2)MR^(2)`
`I_(Z)=2I,I=(1)/(2)I_(Z)`
`I=(1)/(2)xx(1)/(2)MR^(2)=(1)/(4)MR^(2)`
`I=(1)/(4)xx3xx(0.5)^(2)=0.25xx3xx0.5xx0.5`
`I=0.1875kgm^(2)`