Home
Class 12
PHYSICS
White light is passed through a double s...

White light is passed through a double slit and interference pattern is observed on a secreen 2.5 m away. The separation between the slits is 0.5 mm. The first violet and red frings are formed 2.0 mm and 3.5 mm away from the central white fringe. Calculate the wavelegths of the violet and the red light.

Text Solution

Verified by Experts

for the first bright fringe, the distasnce from the centre is
`y=(Dlamda)/d`
for violet light `y=2.0. Thus,
`2.0 mm=((2.5m)lamda)/(0.5mm)`
`or lamda=((0.5mm)(2.0mm))/(2.5mm)=400nm`
`Similarly for red light, y=3.5 mm. thus,
`3.5mm=((2.5m)lamda)/(0.5mm)`
`or lamda=700nm`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A beam of light of lambda= 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is ...

The fraunhofer diffraction pattern of a single slit is formed at the focal plane of a lens of focal length 1m. The width of the slit is 0.3 mm. if the third minimum is formed at a distance of 5 mm from the central maximum then calculate the wavelength of light.

A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen. Find the width of the slit.

In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.

In a Young's double slit experiment, the separation between the slits is 0.15 mm. In the experiment, a source of light of wavelength 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is

Laser light of wavelength 630 nmincident on a pair of slits produces as interference pattern in which the bright fringes are separated by 8.1 mm. A second light produces an interference pattern in which the fringes are separated by 7.2 mm. Calculate the wavelength of the second light.

If the distance between the first maxima and fifth minima of a double-slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light used is

Light of wavelength 6000Å is incident on a slit of width 0.30 mm. The screen is placed 2 m from the slit. Find (a) the position of the first dark fringe and (b). The width of the central bright fringe.

In Young's experiment distance between twe slits is 0.28 mm and distance between the slit and the screen is 1.4 m. If distance between central bright fringe and third bright fringe is 0.9 cm wavelength of light used in Young's experiment is .....

The young's double slit experiment is done in a medium of refractive index 4//3 .A light of 600nm wavelength is falling on the slits having 0.45 mm separation .The lower slit S_(2) is covered by a thin glass sheet of thickness 10.4mu m and refractive index 1.5 .the intereference pattern is observed ona screen placed 1.5m from the slits are shown (a) Find the location of the central maximum (bright fringe with zero path difference)on the y-axis. (b) Find the light intensity at point O relative to the maximum fringe intensity. (c )Now,if 600nm light is replaced by white light of range 400 to700 nm find the wavelength of the light that from maxima exactly point O .[All wavelengths in this problem are for the given medium of refractive index 4//3 .Ignore dispersion]