Home
Class 12
PHYSICS
Using figure (22.1), find the relative l...

Using figure (22.1), find the relative luminosity of wavelength (a) 480 nm, (b) 520 nm (c ) 580 nm and (d) 600 nm.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
It can be found out from the graph by the student.
Promotional Banner

Topper's Solved these Questions

  • PHOTOMETRY

    HC VERMA|Exercise Objective 2|4 Videos

  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA|Exercise Exercise|2 Videos

  • SEMICONDUCTOR AND SEMICONDUCTOR DEVICES

    HC VERMA|Exercise Exercises|35 Videos

Similar Questions

Explore conceptually related problems

Photoelectric effect experiments are performed using three different metal plates p,q and r having work function phi_(p) = 2.0 eV, phi_(e) = 2.5 eV and phi_(r) = 3.0 eV respectively A light beam containing wavelength of 550nm , 450 nm and 350nm with equal intensities illuminates each of the plates . The correct I -V graph for the experiment is [Take hc = 1240 eV nm]

A black body is at a temperature of 2800K The energy of radiation emitted by this object with wavelength between 499nm and 500 nm is U_(1) between 999nm and 1000nm is U_(2) and between 1499 nm and 1500 nm is U_(3) .The Wien's constant b =2.80 xx 10^(6) nm K Then .

If the incident wavelength on a photodiode is 1700 nm, what is its energy gap (E_(g)) ?

The electrical conductivity of a semiconductor of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm, is incident on it. The band gap in (eV) for the semi conductor is ……

In YDSE ,how many maxima can be obtained on the screen if wavelength of light used is 200nm and d=700nm :

Consider a metal exposed to light of wavelength 600nm.The maximum energy of the electron doubles when light of wavelength 400 nm is used .Find the work function in eV.

A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young's double-slit experiment. (a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength 650 nm. (b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide?

The photons from the Balmer series in Hydrogen spectrum having wavelength between 450 nm to 700 nm are incident on a metal surface of work function 2 eV Find the maximum kinetic energy of ejected electron (Given hc = 1242 eV nm)

The figure shows the interfernece pattern obtained in double slit experiment using light of wavelength 600 nm. Q. Let DeltaX_(A) and DeltaX_(C) represent path differences between waves interering at 1 and 3 respectively then (|DeltaX_(C)|-(|DeltaX_(A)|) is equal to