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The horizontal component of the earth's ...

The horizontal component of the earth's magnetic field is `3.6 xx 10^(-5) T` where the dip is `60^@`. Find the magnitude of the earth's magnetic field.

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We have `B_H = B cosdelta`. Or, `B= B_H/(cosdelta) = (3.6 xx 10^(-5) T)/(cos 60^@) - 7.2 xx 10^(-5) T`.
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HC VERMA-PERMANENT MAGNETS-Exercises
  1. The horizontal component of the earth's magnetic field is 3.6 xx 10^(-...

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  2. A long bar magnet has a pole strength of 10 Am. Find the magnetic fiel...

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  3. Two long bar magnets are placed with their axes coinciding in such a w...

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  4. A uniform magnetic field of 0.20 xx 10^(-3) T exists in the space. Fin...

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  5. Figure shows some of the equipotential surfaces of the magnetic scalar...

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  6. The magnetic field at a point, 10cm away from a magnetic dipole, is fo...

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  7. Show that the magnetic field at a point due to a magnetic dipole is pe...

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  8. A bar magnet has a length of 8cm. The magnetic field at a point at a d...

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  9. A magnetic dipole of magnetic moment 1.44 A m^2 is placed horizontally...

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  10. A magnetic dipole of magnetic moment 0.72 Am^2 is planced horizontally...

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  11. A magnetic dipole of magnetic moment 0.72(sqrt(2) Am^2) is placed hori...

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  12. The magnetic moment of the assumed dipole at the earth's centre is 8.0...

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  13. If the earth's magnetic field has a magnitude 3.4 xx 10^(-5) T at the ...

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  14. The magnetic field due to the earth has a horizontal component of 26 m...

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  15. A magnetic needle is free to rotate in a vertical plance which makes a...

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  16. The needle of a dip circle shows an apparent dip of 45^@ in a particul...

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  17. A tangent galvanometer shown a deflection of 45^@ when 10 mA of curren...

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  18. A moving coil galvanometer has a 50-turn coil of size 2cm xx 2cm. It i...

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  19. A short magnet produces a deflection of 37^@ in a deflection magnetome...

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  20. The magnetometer of the previous problem is used with the same magent ...

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  21. A deflection magnetometer is placed with its arms in north-south direc...

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