Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350mn is incident on a cesium surface. Work function of cesium = ` 1.9 e V. `

Explanation

Here ` lambda = 350 nm `
`= 350 xx 10^(-5) m, `
`phi = 1.9 e V`
Max KE of electrons
` = hc/ lambda - phi `
` = 6.63 x 10^(34) xx 3 xx 10^(8) / 350 xx 10^(-9) xx 1.6 xx 10^(-19) - 1.9`
`= 6.63 xx 3 xx 10^(2) / 350 xx 1.6`
`= 1.65 e V = 1.6eV.`