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The lowest frequency of light that will ...

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal ( for which work function is `1.65 eV`) will be

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The correct Answer is:
`4`
The minimum frequency corresponds to threshold frequency `v_(0)`
`:.phi_(0)=hv_(0)`
`:.v_(0)-(phi_(0))/h-(1.655xx1.6xx10^(-19))/(6.62xx10^(-34))-(1.6xx10^(-19))/(4xx10^(34))`
`=4xx10^(14)Hz`
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