In a Young's double slit experiment, fringe width equal to 1 mm is observed. Then the distance of the nearest bright fringe from the central fringe will be :

Options

A. 1 mm
B. `0.5 mm`
C. `2 mm`
D. Insufficient data, cannot be determined

Answer

B

Explanation

Given ,` beta = 1 mm = (D lamda //d)` Distance of 1 st bringht fringe from the centre
`x _(n) = 2n (( D lamda )/( 2d))`
For first bright fringe,
So `x _(1) = (( D lamda )/(d)) = (Dlamda )/(d) = 1 mm`