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If I=50kg m^(2), then how much torque wi...

If `I=50kg m^(2)`, then how much torque will be applied to stop it in 10 sec. Its initial angular speed is 20 rad/sec?

A

100 N -m

B

150 N - m

C

200 N-m

D

250 N - m

Text Solution

Verified by Experts

The correct Answer is:
A
`tau = Ialpha = (Ideltaomega)/(Deltat) = (50(0-20))/10`
`tau = -100 N - m` means
100 N - m in opposite to angular speed.
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