The `DeltaG^@` at 300 K is 2494.2 J for the reaction 2A B + C. At a particular time, the composition of the reaction mixture is [A] = 1/2, [B] = 2 and [C] = `1/2` . The reaction proceeds in the: [R = 8.314 J/K - mol , e=2.718] {Given antilog (-0.44)=0.36}

Options

A. Reverse direction because Q lt `K_c`
B. Forward direction because Q gt `K_c`
C. Reverse direction because Q gt `K_c`
D. Forward direction because Q lt `K_c`

Answer

C

Explanation

`DeltaG^(@)=-RT"ln"K_c`
`2494.2 = -8.314 xx 300 "In" K_c`
`2494.2 = - 8.314 xx 300 xx 2.303 log K_c`
`-(2494.2)/(2.303xx300xx8.314)=-0.44=logK_C`
`=-0.44=1.56`
`K_C`=0.36
`Q_C=(2xx1/2)/((1/2)^(2))=4`
`Q_CgtK_C`, reverse direction.