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For the following reaction, DeltaH, Delt...

For the following reaction, `Delta`H, `DeltaS` and T are 40.63 KJ `mol^(-1)`, 108.8 `JK^(-1)` `mo1^(-1)` and 373.4 K.
Calculate the value of `DeltaG` of reaction (in J) .
`Ag_2O_(s) hArr 2 Ag_(s) + 1/2O_(2(g))`

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The correct Answer is:
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`DeltaG = Deltah - T DeltaS = 40.63 xx 10^3- 108.8 xx 373.4 = 40.063 xx 10^3 - 40.63 xx 10^3` = 0
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