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Enthalpy change for the following reacti...

Enthalpy change for the following reaction
`C_(("graphite"))+2H_(2)(g)toCH_(4)(g)` is
Given:
`Delta_(f)H^(@)(CO_(2(g)))=-393`
`.5kJmol^(-1)`
`Delta_(f)H^(@)(H_(2)O_((1)))=-285`
`.8kJmol^(-1)`
`CO_(2)(g)+2H_(2)O(1)toCH_(4)(g)`
`+2O_(2)(g),Delta_(r)H^(@)=+890`
`.3kJmol^(-1)`

A

`+144.0kJmol^(-1)`

B

`-74.8kJmol^(-1)`

C

`-144.1kJmol^(-1)`

D

`+74.8kJmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
For the reaction
`CO_(2(g))+2H_(2)O_((l))toCH_(4(g))+2O_(2(g))`
`Delta_(r)H^(@)=Sigma(Delta_(f)H^(@))_("products")`
`-sum(Delta_(f)H^(@))_("reactants")`
`=`
`[(Delta_(r)H^(@)(CH_(4))+2xx0)`
`-(Delta_(f)H^(@)(CO_(2))+2Delta_(f)H^(@)(H_(2)O_((l)))]`
`+890.3=[Delta_(f)H(@)(CH_(4))]`
`-[-393.5+2xx(-285.8)]`
`Delta_(f)H^(@)(CH_(4(g)))=-74.8kJ//mol`
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Calculate enthalpy of formation of methane (CH_4) from the following data : (i) C(s) + O_(2)(g) to CO_(2) (g) , Delta_rH^(@) = -393.5 KJ mol^(-1) (ii) H_2(g) + 1/2 O_(2)(g) to H_(2)O(l) , Deta_r H^(@) = -285.5 kJ mol^(-1) (iii) CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l), Delta_(r)H^(@) = -890.3 kJ mol^(-1) .

Given C_(("graphite"))+O_(2)(g)toCO_(2)(g), Delta_(r)H^(0)=-393.5kJ" "mol^(-1) H_(2)(g)=+(1)/(2)O_(2)(g)toH_(2)O(1), Delta_(r)H^(0)=-285.8" kJ "mol^(-1) CO_(2)(g)+2H_(2)O(1)toCH_(4)(g)+2O_(2)(g) , Delta_(r)H^(0)=+890.3kJ" "mol^(-1) Based on the above thermochemical equations, the value of Delta_(r)H^(0) at at 298 K for the reaction C_(("graphite"))+2H_(2)(g)toCH_(4)(g) will be:

Calculate the standard enthalpy of formation of acetylena from the following data: C(s)+O_(2)(g)to CO_(2)(g), DeltaH^(@)=-393.5KJmol^(-1) H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l),DeltaH^(@)=-285 .8KJmol^(-1) 2C_(2)H_(2)(g)+50_(2)(g)to 4Co_(2)(g)+2H_(2)O(l0, DeltaH^(@)=-2598.8KJmol^(-1)

With the help of thermochemical equations given below, determine Delta_(r )H^(Θ) at 298 K for the following reaction: C("graphite")+2H_(2)(g) rarr CH_(4)(g),Delta_(r )H^(Θ) = ? C("graphite")+O_(2)(g) rarr CH_(2)(g), Delta_(r )H^(Θ) = -393.5 kJ mol^(-1) ...(1) H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l) , Delta_(r )H^(Θ) = -285.8 kJ mol^(-1) ...(2) CO_2(2)(g)+2H_(2)O(l) rarr CH_(4)(g)+2O_(2)(g) , Delta_(r )H^(Θ) = +890.3 kJ mol^(-1) ...(3)

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