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A sum of money put out at compound inter...

A sum of money put out at compound interest amounts in 2 years to Rs. 578·40 and in 3 years to Rs. 614·55. Find the rate of interest.

A

`6%`

B

`(6)1/4 %`

C

`(6)1/2 %`

D

`(6)3/4%`

Text Solution

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The correct Answer is:
To find the rate of interest, we can use the information given about the amounts after 2 years and 3 years. Let’s denote: - Amount after 2 years (A2) = Rs. 578.40 - Amount after 3 years (A3) = Rs. 614.55 ### Step 1: Calculate the interest earned in the third year The interest earned in the third year can be calculated by subtracting the amount after 2 years from the amount after 3 years. \[ \text{Interest for 3rd year} = A3 - A2 = 614.55 - 578.40 = 36.15 \] ### Step 2: Calculate the principal amount The amount after 2 years (A2) can be expressed in terms of the principal (P) and the rate of interest (r): \[ A2 = P(1 + r)^2 \] The amount after 3 years (A3) can be expressed as: \[ A3 = P(1 + r)^3 \] ### Step 3: Set up the equation for the third year From the interest earned in the third year, we can express it as: \[ \text{Interest for 3rd year} = A3 - A2 = P(1 + r)^3 - P(1 + r)^2 \] Factoring out \(P(1 + r)^2\): \[ 36.15 = P(1 + r)^2 \cdot r \] ### Step 4: Substitute the value of A2 into the equation From the expression for A2, we can express \(P(1 + r)^2\): \[ P(1 + r)^2 = 578.40 \] ### Step 5: Substitute into the interest equation Now we can substitute this into the interest equation: \[ 36.15 = 578.40 \cdot r \] ### Step 6: Solve for r Now, we can solve for r: \[ r = \frac{36.15}{578.40} \] Calculating this gives: \[ r \approx 0.0625 \] ### Step 7: Convert r to percentage To convert the rate into percentage, we multiply by 100: \[ \text{Rate of interest} = r \times 100 = 0.0625 \times 100 = 6.25\% \] ### Final Answer: The rate of interest is **6.25%**. ---
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