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In each of the following number series ,...

In each of the following number series , a wrong number is given ,find out the wrong number -----
50 51 47 56 42 65 29

A

51

B

47

C

56

D

42

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AI Generated Solution

The correct Answer is:
To find the wrong number in the series 50, 51, 47, 56, 42, 65, 29, we will analyze the pattern in the series step by step. 1. **Identify the Pattern**: - The series appears to alternate between adding and subtracting squares of integers. - Let's denote the terms as follows: - \( a_1 = 50 \) - \( a_2 = 51 \) - \( a_3 = 47 \) - \( a_4 = 56 \) - \( a_5 = 42 \) - \( a_6 = 65 \) - \( a_7 = 29 \) 2. **Calculate Each Term**: - Start with the first term \( a_1 = 50 \). - **Second term**: \( a_2 = a_1 + 1^2 = 50 + 1 = 51 \) (Correct) - **Third term**: \( a_3 = a_2 - 2^2 = 51 - 4 = 47 \) (Correct) - **Fourth term**: \( a_4 = a_3 + 3^2 = 47 + 9 = 56 \) (Correct) - **Fifth term**: \( a_5 = a_4 - 4^2 = 56 - 16 = 40 \) (Expected) - **Sixth term**: \( a_6 = a_5 + 5^2 = 40 + 25 = 65 \) (Correct) - **Seventh term**: \( a_7 = a_6 - 6^2 = 65 - 36 = 29 \) (Correct) 3. **Identify the Wrong Number**: - In the calculation for the fifth term, we expected \( a_5 \) to be 40, but it is given as 42 in the series. - Therefore, the wrong number in the series is **42**. 4. **Conclusion**: - The wrong number in the series is **42**. The correct number should be **40**.
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