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An alkane with mol.mass = 86 on brominat...

An alkane with mol.mass = 86 on bromination gives only two monobromo derivatives (excluding stereoisomers). The alkane is

A

`CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - CH_(2) - CH_(3)`

B

`CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - CH_(2) - CH_(3)`

C

`CH_(3) - underset(CH_(3))underset(|)(CH) - underset(CH_(3))underset(|)(CH) - CH_(3)`

D

`CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Mol. wt. = 86 `therefore` Mol. formula `= C_(6) H_(14)`
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