Home
Class 12
CHEMISTRY
Heating benzene in a large excess of 80%...

Heating benzene in a large excess of 80% `D_2SO_4` in `D_2O` results in what product ?

A

`C_6H_5SO_3D`

B

`C_6H_5OD`

C

`C_6H_5D`

D

`C_6D_6`

Text Solution

Verified by Experts

The correct Answer is:
D


all hydrogen will be replaced by deuterium.
Promotional Banner

Topper's Solved these Questions

  • AROMATIC COMPOUNDS

    MS CHOUHAN|Exercise LEVEL-2|11 Videos
  • AROMATIC COMPOUNDS

    MS CHOUHAN|Exercise LEVEL-2 (COMPREHENSION)|16 Videos
  • AMINES

    MS CHOUHAN|Exercise Level-2|1 Videos
  • BIOMOLECULES

    MS CHOUHAN|Exercise LEVEL - 2|5 Videos

Similar Questions

Explore conceptually related problems

Consider the nitration of benzene using mixed conc. H_2SO_4 and HNO_3 If a large amount of KHSO_4 is added to the mixture, the rate of nitration will be

When 2-butanol is heated with an excess of concentrated sulphuric acid, the main product is

When BiCl_3 is dissolved in excess of D_2O , the product formed is

Aniline or reaction with con. H_(2)SO_(4) gives X. If X is heated, the product is

D_2O reacts with P_2O_5 and gives

The purpose of adding conc. H_(2)SO_(4) in nitration of benzene is to produce

A physical quantity P is related to four quantities a,b , c and d as follows . P = (a^3 b^2)/(sqrt(c) d) The percentage errors of measurement in a,b , c and d are 1% , 3% , 4% and 2% respectively . What is the percentage error in the quantity P ?