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An element with density 2.8 g cm^(-3) f...

An element with density 2.8 g `cm^(-3)` forms a fee unit cell with edge length `4 xx 10^(-8)` cm. Calculate the molar mass of the element.

A

`42g "mol"^(-1)`

B

`27g "mol"^(-1)`

C

`36g "mol"^(-1)`

D

`28g "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
` therefore d = (ZxxM)/(a^3 xx N_A)`
`rArr M = ( d xx a^3 xx N_A)/(Z) = (2.8 xx (4 xx 10^(-8))^3 xx 6.022 xx 10^23)/(4)`
`rArr 2.8 xx 16 xx 10^(-1) xx 6.022`
`rArr M = (269.78)/(10) = 26.978 = 27 g"mol"^(-1)`
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