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A bcc element (atomic mass 65) has a cel...

A bcc element (atomic mass 65) has a cell edge of 420 pm. Calculate its density in g/`cm^3`

A

`2.25 g cm^(-3)`

B

`2.97 gcm^(-3)`

C

`2.84 g cm^(-3)`

D

`2.91 gcm^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
D

`therefore rho = (2 xx 65)/((420 xx 10^(-10))^3 xx 6.023 xx 10^23)`
` = (2 xx 65 xx 10^4)/((42)^3 xx 6.023)`
` = 2.91 gcm^(-3)`
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