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Which will have largest Delta T(b)...

Which will have largest `Delta T_(b)`

A

65 g urea in 1 kg water

B

18 g glucose in 100 g water

C

342 g sucrose in 1000 g water

D

180 g glucose in 1 kg water

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To determine which solution will have the largest ΔT_b (elevation in boiling point), we need to calculate the molality of each solution, as ΔT_b is directly proportional to molality (ΔT_b = k_b * m, where k_b is the molal elevation constant and m is the molality). ### Step-by-Step Solution: 1. **Understanding Molality**: - Molality (m) is defined as the number of moles of solute per kilogram of solvent. - Formula: \( m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} \) 2. **Calculate Molality for Each Solution**: **Option 1: Urea in Water** - Given: 65 grams of urea and 1 kg of water. - Molar mass of urea (NH₂CONH₂) = 60 g/mol. - Moles of urea = \( \frac{65 \text{ g}}{60 \text{ g/mol}} = 1.0833 \text{ mol} \). - Molality (m) = \( \frac{1.0833 \text{ mol}}{1 \text{ kg}} = 1.0833 \text{ mol/kg} \). **Option 2: Glucose in Water** - Given: 18 grams of glucose and 100 grams of water. - Molar mass of glucose (C₆H₁₂O₆) = 180 g/mol. - Moles of glucose = \( \frac{18 \text{ g}}{180 \text{ g/mol}} = 0.1 \text{ mol} \). - Mass of water = 100 g = 0.1 kg. - Molality (m) = \( \frac{0.1 \text{ mol}}{0.1 \text{ kg}} = 1.0 \text{ mol/kg} \). **Option 3: Sucrose in Water** - Given: 342 grams of sucrose and 1000 grams of water. - Molar mass of sucrose (C₁₂H₂₂O₁₁) = 342 g/mol. - Moles of sucrose = \( \frac{342 \text{ g}}{342 \text{ g/mol}} = 1.0 \text{ mol} \). - Mass of water = 1000 g = 1 kg. - Molality (m) = \( \frac{1.0 \text{ mol}}{1.0 \text{ kg}} = 1.0 \text{ mol/kg} \). **Option 4: Glucose in Water** - Given: 18 grams of glucose and 1 kg of water. - Molar mass of glucose = 180 g/mol. - Moles of glucose = \( \frac{18 \text{ g}}{180 \text{ g/mol}} = 0.1 \text{ mol} \). - Mass of water = 1 kg. - Molality (m) = \( \frac{0.1 \text{ mol}}{1 \text{ kg}} = 0.1 \text{ mol/kg} \). 3. **Compare the Molalities**: - Urea: 1.0833 mol/kg - Glucose (100 g water): 1.0 mol/kg - Sucrose: 1.0 mol/kg - Glucose (1 kg water): 0.1 mol/kg 4. **Conclusion**: - The solution with the highest molality is the one with urea, which has a molality of approximately 1.0833 mol/kg. - Therefore, the solution that will have the largest ΔT_b is the one containing urea. ### Final Answer: **Option 1: Urea in Water will have the largest ΔT_b.**

To determine which solution will have the largest ΔT_b (elevation in boiling point), we need to calculate the molality of each solution, as ΔT_b is directly proportional to molality (ΔT_b = k_b * m, where k_b is the molal elevation constant and m is the molality). ### Step-by-Step Solution: 1. **Understanding Molality**: - Molality (m) is defined as the number of moles of solute per kilogram of solvent. - Formula: \( m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} \) ...
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