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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction` Fe + CuSO_4 ⇌ FeSO_4 + Cu` at 25°C. (Given E°(OP/Fe) = 0.5 V°, E°(OP/Cu) = -0.4 V)

A

`3.46 xx 10^(30)`

B

` 3.46 xx 10 ^(26)`

C

` 3 . 32 xx 10^(30)`

D

`3.22 xx 10 ^(26)`

Text Solution

Verified by Experts

The correct Answer is:
C
The cell reaction shows oxidation of Fe and reduction of ` Cu^(2+)`
`Fe + CuSO_(4) hArr FeSO_(4) + Cu`
`E_(("cell"))^(@) = E_(("OP/Fe"))^(@) + E_(("RP /Cu"))^(@)`
`E_(("Cell"))^(@) = 0 . 5 + 0 . 4 = 0 . 9 V `
We have, ` E^(@) = 0.0592 log_(10) K_(c)`
`0.9 = 0.0592 log10 K_(c)`
`K_(c) = 3 . 22 xx 10 ^(30)`
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