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Given that sin theta = p/q then tanthe...

Given that `sin theta = p/q` then `tantheta` is equal to

A

`(p)/(sqrt(p^2 - q^2))`

B

`(q)/(sqrt(p^2 - q^2))` s

C

`(p)/(sqrt(q^2 - p^2))`

D

`(q)/(sqrt(q^2 - p^2))`

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