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When an alternating voltage E = E(0) sin...

When an alternating voltage `E = E_(0) sin omegat` is applied to a circuit , a current ` I= I_(0) sin(omega t + (pi)/(2))` flows through it . The average power dissipated in the circuit is

A

`E_("rms") I_("rms")`

B

`E_(0) I_(0)`

C

`(E_(0)I_(0))/(sqrt(2))`

D

Zero

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