Consider the two function f: R to R giv...

Consider the two function `f: R to R ` given by ` f(x) = x-2 and g: R to R` given by `g(x) = x^(2)`
The value of ` f(1) + g(1) ` is :

A

`1/2`

B

0

C

1

D

`(-1)/(2)`

Verified by Experts

Similar Questions

Explore conceptually related problems

The function f:R to R given by f(x)=x^(2)+x is

If the function f: R->R be given by f(x)=x^2+2 and g: R->R be given by g(x)=x/(x-1) . Find fog and gof .

If f:R to R be defined by f(x)=3x^(2)-5 and g: R to R by g(x)= (x)/(x^(2)+1). Then, gof is

Consider the function f:R -{1} to R -{2} given by f {x} =(2x)/(x-1). Then

Consider the function f:R -{1} given by f (x)= (2x)/(x-1) Then f^(-1)(x) =

Consider a function f:[0,pi/2]->R given by f(x)=sin x and g:[0,pi/2]->R given by g(x)=cos x. Show that f and g are one-one, but f+g is not one-one.

If f : R rarr R, f(x) = x^(2) + 2x - 3 and g : R rarr R, g(x) = 3x - 4 then the value of fog (x) is

If f: R->R , g: R->R are given by f(x)=(x+1)^2 and g(x)=x^2+1 , then write the value of fog\ (-3) .

If f : R rarr R, f(x) = x^(2) - 5x + 4 and g : R^(+) rarr R, g(x) = log x , then the value of (gof) (2) is

If f : R to R , f(x)=x^(2) and g(x)=2x+1 , then