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Two identical spheres of radius R, made ...

Two identical spheres of radius R, made of a material of density `rho`, are in contact with each other. If the gravitational attraction between them is F, then

A

`F prop (rho^2)/(R^2)`

B

`F prop rho^2 R^4`

C

`F prop (rho^4)/(R^6)`

D

`F prop rho^4 R^4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the gravitational attraction \( F \) between two identical spheres of radius \( R \) and density \( \rho \), we can follow these steps: ### Step 1: Determine the mass of one sphere The mass \( m \) of a sphere can be calculated using the formula: \[ m = \text{Volume} \times \text{Density} \] The volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi R^3 \] Thus, the mass of one sphere becomes: \[ m = \frac{4}{3} \pi R^3 \rho \] ### Step 2: Calculate the distance between the centers of the spheres Since the two spheres are in contact, the distance \( d \) between their centers is equal to the sum of their radii: \[ d = R + R = 2R \] ### Step 3: Apply Newton's law of gravitation According to Newton's law of gravitation, the gravitational force \( F \) between two masses \( m_1 \) and \( m_2 \) separated by a distance \( d \) is given by: \[ F = \frac{G m_1 m_2}{d^2} \] For our two spheres, both have the same mass \( m \), so: \[ F = \frac{G m^2}{(2R)^2} \] ### Step 4: Substitute the mass into the gravitational force equation Substituting the expression for mass \( m \) into the gravitational force equation: \[ F = \frac{G \left(\frac{4}{3} \pi R^3 \rho\right)^2}{(2R)^2} \] ### Step 5: Simplify the expression Now, we simplify the expression: \[ F = \frac{G \left(\frac{16}{9} \pi^2 R^6 \rho^2\right)}{4R^2} \] This simplifies to: \[ F = \frac{4G \pi^2 R^6 \rho^2}{9R^2} = \frac{4G \pi^2 R^4 \rho^2}{9} \] ### Step 6: Conclusion From the final expression, we can conclude that the gravitational force \( F \) is directly proportional to \( R^4 \) and \( \rho^2 \): \[ F \propto R^4 \rho^2 \] ### Final Answer Thus, the gravitational attraction \( F \) between the two spheres is proportional to \( R^4 \) and \( \rho^2 \). ---
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