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5(1/4) kg of oranges and 2(3/5)kg of gra...

`5(1/4)` kg of oranges and `2(3/5)`kg of grapes were bought together by Alisha from the supermarket. What is the total weight of the fruits will she be carrying out of supermarket ?

A

`8(5/13)` kg

B

`7(17/20)` kg

C

`7(17/21)` kg

D

`8(9/13)` kg

Text Solution

AI Generated Solution

The correct Answer is:
To find the total weight of fruits Alisha bought, we need to add the weight of the oranges and the weight of the grapes. Let's break it down step by step. ### Step 1: Convert the mixed numbers to improper fractions 1. **Weight of Oranges**: \(5 \frac{1}{4}\) kg - Convert to an improper fraction: \[ 5 \frac{1}{4} = \frac{(5 \times 4) + 1}{4} = \frac{20 + 1}{4} = \frac{21}{4} \text{ kg} \] 2. **Weight of Grapes**: \(2 \frac{3}{5}\) kg - Convert to an improper fraction: \[ 2 \frac{3}{5} = \frac{(2 \times 5) + 3}{5} = \frac{10 + 3}{5} = \frac{13}{5} \text{ kg} \] ### Step 2: Find a common denominator To add the two fractions \(\frac{21}{4}\) and \(\frac{13}{5}\), we need a common denominator. The least common multiple (LCM) of 4 and 5 is 20. ### Step 3: Convert the fractions to have the common denominator 1. Convert \(\frac{21}{4}\): \[ \frac{21}{4} = \frac{21 \times 5}{4 \times 5} = \frac{105}{20} \] 2. Convert \(\frac{13}{5}\): \[ \frac{13}{5} = \frac{13 \times 4}{5 \times 4} = \frac{52}{20} \] ### Step 4: Add the two fractions Now we can add the two fractions: \[ \frac{105}{20} + \frac{52}{20} = \frac{105 + 52}{20} = \frac{157}{20} \] ### Step 5: Convert the improper fraction to a mixed number To convert \(\frac{157}{20}\) to a mixed number: - Divide 157 by 20: - 20 goes into 157 seven times (since \(20 \times 7 = 140\)). - The remainder is \(157 - 140 = 17\). Thus, we can write: \[ \frac{157}{20} = 7 \frac{17}{20} \text{ kg} \] ### Final Answer The total weight of the fruits Alisha will be carrying out of the supermarket is \(7 \frac{17}{20}\) kg. ---
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