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Raghav had ₹ (6x^(3) + 2x^(2) + 3x) and ...

Raghav had ₹ `(6x^(3) + 2x^(2) + 3x)` and he bought `(4x^(2) + 3)` shirts. The price of each shirt is ₹ (x + 5). How much money is left with Raghav?

A

`₹ (2x^(3) - 18x^(2) -15)`

B

`₹ (4x^(2) + 2x +3)`

C

`₹( x^(3)-3x)`

D

`₹( 2x^(3) + 2x^(2) -15)`

Text Solution

AI Generated Solution

The correct Answer is:
To find out how much money is left with Raghav after buying the shirts, we will follow these steps: ### Step 1: Determine the total amount Raghav had initially. Raghav had ₹ (6x³ + 2x² + 3x). ### Step 2: Calculate the total cost of the shirts. Raghav bought (4x² + 3) shirts, and the price of each shirt is (x + 5) rupees. To find the total cost of the shirts, we multiply the number of shirts by the price of each shirt: \[ \text{Total Cost} = \text{Number of Shirts} \times \text{Price per Shirt} \] \[ \text{Total Cost} = (4x² + 3)(x + 5) \] ### Step 3: Expand the expression for the total cost. Using the distributive property (also known as the FOIL method for binomials): \[ (4x² + 3)(x + 5) = 4x² \cdot x + 4x² \cdot 5 + 3 \cdot x + 3 \cdot 5 \] \[ = 4x³ + 20x² + 3x + 15 \] ### Step 4: Subtract the total cost from the initial amount. Now, we will subtract the total cost from the initial amount Raghav had: \[ \text{Money Left} = \text{Initial Amount} - \text{Total Cost} \] \[ \text{Money Left} = (6x³ + 2x² + 3x) - (4x³ + 20x² + 3x + 15) \] ### Step 5: Simplify the expression. Now we will combine like terms: \[ \text{Money Left} = (6x³ - 4x³) + (2x² - 20x²) + (3x - 3x) - 15 \] \[ = 2x³ - 18x² - 15 \] ### Final Answer: Thus, the amount of money left with Raghav is: \[ \text{Money Left} = 2x³ - 18x² - 15 \] ---
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