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Derive an expression for the frequency of radiation emitted when a hydrogen atom de-excites from level n to level (n – 1). Also show that for large values of n, this frequency equals to classical frequency of revolution of an electron.

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Obtain an epression for the frequency of radiation emitted when a hydrogen atom de- excites from levle (n-1). For large n, show that this frequency equals to classical frequency of revolution of the electron in the orbit .

The frequency of radiations , emitted when the electron falls , from n=4 to n=1 in a hydrogen , atom

Knowledge Check

  • The frequency corresponding to transition n = 1 to n = 2 in hydrogen atom is.

    A
    `15.66 xx 10^10 Hz`
    B
    `24.66 xx 10^14 Hz`
    C
    `30.57 xx 10^14 Hz`
    D
    `40.57 xx 10^24 Hz`
  • If the frequency of revolution of electron in an orbit H atom is n then the equivalent current is

    A
    `(2pi r e)/n`
    B
    `(en)/(2pi r)`
    C
    `e^(2) pi n`
    D
    en
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    Using Bohr's postualtes , derive the expression for the frequency of radiation emitted when electron in hydrogen atom undergoes transition from higher energy state ( quantum number n_(i) ) to the lower state (n_(f)) . When electron in hydrogen atom jumps from energy state n_(i) = 4 to n_(f) = 3,2,1 identify the spectral series to which the emission lines belong .

    Calculate the energy and frequency of the radiation emitted when an electron jumps from n=3 to n=2 ina hydrogen atom.

    Using Bohr's theory show that when n is very large the frequency of radiation emitted by hydrogen atom due to transition of electrom from n to (n-1) is equal to frequency of revolution of electron in its orbit.

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