"If the slits in Young's double slit experiment are identical, then intensity at any point on the screen may vary between zero and four times to the intensity due to single slit". Justify the above statement through a relevant mathematical expression.

Youngs Double slit experiment | variation of intensity on screen

In a Young's double slit experiment, the central point on the screen is

In Young's double slit experiment, phase difference between the waves at a point on screen having intensity less than the average intensity on screen may be

Slit widths in a young double slit experiment are in the ratio 9:4 . Ratio of intensity at minima to that at maxima is

In Young's double slit experiment, the maximum intensity is I_(0) . What is the intensity at a point on the screen where the path difference between the interfering waves is lamda/4 ?

In the standard Young's double slit experiment, the intensity on the screen at a point distant 1.25 fringe widths from the central maximum is (assuming slits to be identical)

In Young's double slit experiment, if the widths of the slits are in the ratio 4:9, the ratio of the intensity at maxima to the intensity at minima will be

In Young's double slit experiment, if the widths of the slits are in the ratio 4:9 , the ratio of the intensity at maxima to the intensity at minima will be

In young's double slit experiment relative intensity at a point on the screen may be defined as ratio of intensity at that point to the maximum intensity on the screen. Light of wavelength 7500overset(@)A A passing through a double slit, produces interference pattern of relative intensity variation as shown in Fig. theta on horizontal axis represents the angular position of a point on the screen (a) Find separation d between the slits. (b) Find the ratio of amplitudes of the two waves producing interference pattern on the screen.