Savita walks 20 m to the West, then turns left and walks 18 m , then again turns left and walks 13m , and the turns right and walks 6m . How far and in which direction is she now eith respect to the starting point ?

Options

A. 25m, South -East
B. 25m, South - West
C. 24 m , South - East
D. 20m , South

Explanation

To solve the problem step by step, we will track Savita's movements and calculate her final position relative to her starting point.

### Step-by-Step Solution:

1. **Starting Point**: Assume Savita starts at point O (0, 0).

2. **First Move**: Savita walks 20 m to the West.
- New position: O (0, 0) → A (-20, 0)

3. **Second Move**: Savita turns left (now facing South) and walks 18 m.
- New position: A (-20, 0) → B (-20, -18)

4. **Third Move**: Savita turns left again (now facing East) and walks 13 m.
- New position: B (-20, -18) → C (-20 + 13, -18) = C (-7, -18)

5. **Fourth Move**: Savita turns right (now facing South) and walks 6 m.
- New position: C (-7, -18) → D (-7, -18 - 6) = D (-7, -24)

6. **Final Position**: Savita's final position is D (-7, -24).

7. **Distance from Starting Point**: To find the distance from the starting point O (0, 0) to D (-7, -24), we use the distance formula:
\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
\[ \text{Distance} = \sqrt{(-7 - 0)^2 + (-24 - 0)^2} = \sqrt{(-7)^2 + (-24)^2} = \sqrt{49 + 576} = \sqrt{625} = 25 \text{ m} \]

8. **Direction**: To determine the direction, we can use the coordinates of the final position. Since the final position is in the third quadrant (both x and y are negative), the direction is South-West.

### Final Answer:
Savita is 25 m away from the starting point in the South-West direction.