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The diagram shows the velocity-time grap...

The diagram shows the velocity-time graph of two moving cars P and Q. The graph indicates that

A

The velocity of car P is increasing at a decreasing rate from 40 s to 45 s in same direction.

B

Car Q is moving with a constant acceleration from 0 to 40 seconds

C

Acceration of the car Q is not zero at any point during whole journey .

D

After 20 s, P is bihind Q.

Text Solution

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The correct Answer is:
A

From 40 s to 45 s direction of car P is same but velocity is increasing at a decreasing rate of accleration .
(ii) Acceleration of car Q from 0 to t seconds is
`(50-0)/(20-0) = 2.5 m s^(-2) ` i.e., constant and after t is becomes zero.
(iii) Acceleration of the car Q is zero from t to 70 s , so velocity is constant.
(iv) Distance travelled by P at the end of first 20 s `= 1/2 xx 50 xx (10+ 20) = 750 m`
Distance travelled by Q at the end of first 20 s `= 1/2 xx 50 xx 20 = 250 m`
After 20 s , Q is behind P by 250 m
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