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Consider the following figures 1 and 2. ...

Consider the following figures 1 and 2. In figure 1, the mass of the body A in air is 0.2 kg. The mass of the water container (with water in it) is 0.5 kg. In figure 2, when A is completely immersed in the water of the container B, the readings of the respective balances change as shown.

What is the value of X?

A

0.55 kg

B

0.15 kg

C

0.3 kg

D

0.45 kg

Text Solution

Verified by Experts

The correct Answer is:
A
Initially, weight of A = 0.2 kg wt
Weight of B = 0.5 kg wt
After complete immersion of A in water,
Weight of A = 0.15 kg wt
Reduction in weight of A = 0.2 - 0.15 = 0.05 kg wt
So, buoyant force applied on A by water = 0.05 kg wt
Required weight = weight of B + buoyant force on A
`= 0.5 + 0.05 = 0.55` kg wt
The reading of X = 0.55 kg
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