Riya buys a bag of sugar of weight Wat a place on the equator. She takes it to Antarctica. The weight of a sugar bag at Antarctica

Options

A. Increases
B. Decreases
C. Remains same as the weight at a place on equator
D. Cannot be said.

Explanation

To determine the weight of Riya's bag of sugar when she takes it from the equator to Antarctica, we will analyze the factors affecting weight due to gravity.

### Step-by-Step Solution:

1. **Understanding Weight**:
- Weight (W) is defined as the force exerted by gravity on an object. It is calculated using the formula:
\[ W = mg \]
where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity.

2. **Weight at the Equator**:
- At the equator, the weight of the sugar bag is given as \( W \). This weight is influenced by the gravitational pull of the Earth, which is approximately \( g = 9.81 \, \text{m/s}^2 \) at sea level.

3. **Weight in Antarctica**:
- Antarctica is located at the South Pole. The acceleration due to gravity varies slightly across the surface of the Earth. It is generally stronger at the poles compared to the equator due to the Earth's shape (it is an oblate spheroid) and the centrifugal force caused by the Earth's rotation.

4. **Comparing Gravitational Acceleration**:
- The value of \( g \) is slightly higher at the poles than at the equator. For example, at the poles, \( g \) can be approximately \( 9.83 \, \text{m/s}^2 \).

5. **Calculating Weight in Antarctica**:
- When Riya takes the sugar bag to Antarctica, the weight can be recalculated using the higher value of \( g \):
\[ W' = mg' \]
where \( g' \) is the acceleration due to gravity in Antarctica (approximately \( 9.83 \, \text{m/s}^2 \)). Since \( g' > g \), the weight \( W' \) will be greater than the original weight \( W \).

6. **Conclusion**:
- Therefore, the weight of the sugar bag in Antarctica will **increase** compared to its weight at the equator.

### Final Answer:
The weight of the sugar bag at Antarctica **increases**.

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