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Each member of a party contributed thric...

Each member of a party contributed thrice as many rupees as the total number of members and the total collection was Rs 7203. How many members contributed for the party?

A

49

B

39

C

26

D

46

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, let's denote the number of members in the party as \( n \). 1. **Understanding the Contribution**: Each member contributed thrice the total number of members. Therefore, the contribution of each member can be expressed as: \[ \text{Contribution of each member} = 3n \] 2. **Total Contribution**: Since there are \( n \) members, the total contribution from all members can be calculated as: \[ \text{Total Contribution} = n \times \text{Contribution of each member} = n \times 3n = 3n^2 \] 3. **Setting Up the Equation**: According to the problem, the total collection was Rs 7203. Therefore, we can set up the equation: \[ 3n^2 = 7203 \] 4. **Solving for \( n^2 \)**: To find \( n^2 \), we divide both sides of the equation by 3: \[ n^2 = \frac{7203}{3} = 2401 \] 5. **Finding \( n \)**: Now, we need to find \( n \) by taking the square root of \( n^2 \): \[ n = \sqrt{2401} \] 6. **Calculating the Square Root**: The square root of 2401 is 49, so: \[ n = 49 \] Thus, the number of members who contributed for the party is **49**.
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