Home
Class 8
MATHS
State 'T' for true and 'F' for false and...

State 'T' for true and 'F' for false and select the correct option.
(i) The measure of each exterior angle of an n-sided regular polygon is `((180^(@))/(n))`.
(ii) The adjacent angles in a parallelogram are supplementary.
(iii) In a quadrilateral PQRS, the bisector of `angleP and angleQ` meet at point M. If `angleR = 120^(@) and angleS = 40^(@)`, then `anglePMQ = 80^(@)`

A

`{:(i,ii,iii),(F,F,T):}`

B

`{:(i,ii,iii),(F,T,T):}`

C

`{:(i,ii,iii),(T,F,F):}`

D

`{:(i,ii,iii),(T,T,F):}`

Text Solution

AI Generated Solution

The correct Answer is:
Let's solve the question step by step. ### Step 1: Evaluate Statement (i) **Statement:** The measure of each exterior angle of an n-sided regular polygon is \(\frac{180^\circ}{n}\). **Solution:** - The formula for the measure of each exterior angle of a regular polygon is actually \(\frac{360^\circ}{n}\), not \(\frac{180^\circ}{n}\). - Therefore, this statement is **False (F)**. ### Step 2: Evaluate Statement (ii) **Statement:** The adjacent angles in a parallelogram are supplementary. **Solution:** - In a parallelogram, adjacent angles are indeed supplementary, meaning their sum is \(180^\circ\). - This is a property of parallelograms, so this statement is **True (T)**. ### Step 3: Evaluate Statement (iii) **Statement:** In a quadrilateral PQRS, the bisector of angle P and angle Q meet at point M. If \(\angle R = 120^\circ\) and \(\angle S = 40^\circ\), then \(\angle PMQ = 80^\circ\). **Solution:** 1. Let \(\angle P = 2x\) and \(\angle Q = 2y\) (since they are bisected). 2. The sum of the angles in a quadrilateral is \(360^\circ\): \[ 2x + 2y + \angle R + \angle S = 360^\circ \] Substituting the known angles: \[ 2x + 2y + 120^\circ + 40^\circ = 360^\circ \] Simplifying gives: \[ 2x + 2y + 160^\circ = 360^\circ \] \[ 2x + 2y = 200^\circ \] \[ x + y = 100^\circ \] 3. In triangle PMQ, the sum of the angles is \(180^\circ\): \[ x + y + \angle PMQ = 180^\circ \] Substituting \(x + y = 100^\circ\): \[ 100^\circ + \angle PMQ = 180^\circ \] Therefore: \[ \angle PMQ = 180^\circ - 100^\circ = 80^\circ \] This statement is **True (T)**. ### Final Evaluation: - (i) **False (F)** - (ii) **True (T)** - (iii) **True (T)** ### Correct Option: The correct option is the one that states (i) is False, (ii) is True, and (iii) is True. ---
Promotional Banner

Topper's Solved these Questions

  • IMO QUESTION PAPER 2018-19 SET- A

    SCIENCE OLYMPIAD FOUNDATION |Exercise Everyday Mathematics|10 Videos
  • IMO QUESTION PAPER 2018-19 SET -B

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2019-20 SET A

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|5 Videos

Similar Questions

Explore conceptually related problems

Find the measure of each exterior angle of a regular polygon of ( i ) 9 sides (ii) 15 sides

Find the measure of each exterior angle of a regular polygon of : (i) 8 sides , (ii) 9 sides , (iii) 12 sides

Passage II: Measure of each exterior angle of a regular polygon of n sides : (360/n)^(@) The measure of each exterior angle of a 10 sided regular polygon is

Find the measure of each exterior angle of a regular (i) pentagon (ii) hexagon (iii) heptagon (iv) decagon (v) polygon of 15 sides.

Find the measure of each interior angle of a regular (i) pentagon (ii) hexagon (iii) octagon (iv) polygon of 12 sides

Passage II: Measure of each exterior angle of a regular polygon of n sides : (360/n)^(@) If measure of an exterior angle is 45^(@) , the number of sides in a regular polygon is

Assertion: The measure of each angle of a regular hexagon is 120^(@) Reason: Sum of all interior angles of a polygon of n sides is (n-2) right angles.

Study the given statements carefully. State T for true and 'F' for false and select the correct option. (i) If a number is a factor of each of the given two numbers, then it must be factor of their a difference. (ii) If a number is divisible by another number, then it must be divisible by each of the factors of that number. (iii) If a number is divisible by another number, then it is also divisible by all the multiples of that number. (iv)No prime number other than 2 is even but every odd number is necessarily a prime number.