To solve the question, we need to identify the elements X and Y based on the information provided about their ionization states and electronic configurations.
### Step-by-Step Solution:
1. **Understanding the Ionization States**:
- Element X forms a stable dipositive ion (X²⁺), which means it loses 2 electrons.
- Element Y forms a stable dinegative ion (Y²⁻), which means it gains 2 electrons.
2. **Determining the Electronic Configuration**:
- Both elements X and Y have octet configurations in their L shell. This means they have 8 electrons in their outermost shell (L shell).
- The electronic configuration for an element with 8 electrons in the L shell is 2, 8.
3. **Finding Element X**:
- For element X to form a dipositive ion (X²⁺), it must originally have 10 electrons (2 in K shell and 8 in L shell).
- Therefore, the electronic configuration of element X is 2, 8.
4. **Finding the Succeeding Element of X**:
- The succeeding element of X would have one more electron than X.
- If X has the configuration 2, 8, the succeeding element would have the configuration 2, 8, 1 (which corresponds to element Y in the M shell).
- Thus, the electronic configuration of the succeeding element of X is **2, 8, 1**.
5. **Finding Element Y**:
- For element Y to form a dinegative ion (Y²⁻), it must originally have 6 electrons in its outer shell (L shell) before gaining 2 electrons.
- Therefore, the electronic configuration of element Y is 2, 6.
6. **Finding the Preceding Element of Y**:
- The preceding element of Y would have one less electron than Y.
- If Y has the configuration 2, 6, the preceding element would have the configuration 2, 5.
- Thus, the electronic configuration of the preceding element of Y is **2, 5**.
### Final Answer:
- The electronic configuration of the succeeding element of X is **2, 8, 1**.
- The electronic configuration of the preceding element of Y is **2, 5**.
